q=3q^2-16q+30

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Solution for q=3q^2-16q+30 equation: 



q=3q^2-16q+30

We move all terms to the left:

q-(3q^2-16q+30)=0

We get rid of parentheses

-3q^2+q+16q-30=0

We add all the numbers together, and all the variables

-3q^2+17q-30=0

a = -3; b = 17; c = -30;
Δ = b2-4ac
Δ = 172-4·(-3)·(-30)
Δ = -71
Delta is less than zero, so there is no solution for the equation

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